Sets
4 Board Maths previous year questions on Sets — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.
A survey shows that 63% of the people in a city read newspaper A whereas 76% read newspaper B. If x% of the people read both the newspapers, then a possible value of can be:
55
Let the total number of people in the city be \( 100 \).
Also, let \( A \) denotes the set of people who read
newspaper \( A \) and \( B \) denotes the set of people who
read newspaper \( B \).
\[ n(A)=63, n(B)=76 \]
Clearly, \( n(A \cup B) \) Clearly
\[ \begin{aligned} & \Rightarrow \quad n(A)+n(B)-n(A \cap B) \leq 100 \\ & \Rightarrow \quad 63+76-x \leq 100 \Rightarrow x \geq 39 \\ & \text { Also, } x \leq 63 \quad \therefore 39 \leq x \leq 63 \end{aligned} \]
Also, \( x \leq 63 \quad \therefore 39 \leq x \leq 63 \)
So, the possible value of \( x \) can be \( 55 \).
If \(A=\{x \in R:|x|<2\}\) and \(B=\{x \in R:|x-2| \geq 3\}\), then:
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A set A has 3 elements and another set B has 6 elements. Then
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Consider the two sets: \(A=\left{m\in R\right.\) : both the roots of \({x}^{2}-(m+1)\)\(x=m+4\) are real} and \(B=[-3,5).\) Which of the following is not true?
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