🏫 Board🧪 Chemistry

At temperature T, compound \(A{B}_{2(g)}\) dissociates as \(A{B}_{2(g)}⇌AB(g)+\frac{1}{2}{B}_{2(g)}\) having degree of d…

Q1

At temperature T, compound \(A{B}_{2(g)}\) dissociates as \(A{B}_{2(g)}⇌AB(g)+\frac{1}{2}{B}_{2(g)}\) having degree of dissociation x (small compared to unity). The correct expression for x in terms of \({K}_{p}\) and p is

a

\(\sqrt[3]{\frac{2{K}_{p}^{2}}{p}}\)

b

\(\sqrt{{K}_{p}}\)

c

\(\sqrt[3]{\frac{2{K}_{p}}{p}}\)

d

\(\sqrt[4]{\frac{2{K}_{p}}{p}}\)

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