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\({\mathrm{CO}}_{2}(\mathrm{g})+\mathrm{C}(\mathrm{s})⇌2\mathrm{CO}(\mathrm{g})\) If initial pressure of \({\mathrm{CO}}…

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\({\mathrm{CO}}_{2}(\mathrm{g})+\mathrm{C}(\mathrm{s})⇌2\mathrm{CO}(\mathrm{g})\)

If initial pressure of \({\mathrm{CO}}_{2}\)is 0.6 atm and after equilibrium is established, total pressure is 0/8 atm. Then, find \({\mathrm{K}}_{\mathrm{p}}\).

(Memory Based JEE Mains 22/01/2025, Shift -1)

a

0.4

b

0.2

c

0.6

d

0.8

✓ Correct answer: a)

0.4

Explanation

\({\mathrm{CO}}_{2}(\mathrm{g})+\mathrm{C}(\mathrm{s})⇌2\mathrm{CO}(\mathrm{g})\\ \mathrm{At}\mathrm{t}=0{\mathrm{p}}_{0}--\\ \mathrm{At}\mathrm{t}=\mathrm{teq}{\mathrm{p}}_{0}-\mathrm{p}2\mathrm{p}\\ {\mathrm{P}}_{\mathrm{T}}={\mathrm{P}}_{0}+\mathrm{P}\Rightarrow \mathrm{p}=(0.8-0.6)=0.2,{\mathrm{p}}_{\mathrm{CO}}=0.4\mathrm{and}{\mathrm{p}}_{{\mathrm{CO}}_{2}}=0.4\\ {\mathrm{K}}_{\mathrm{p}}=\frac{{\mathrm{p}}_{{(\mathrm{CO})}^{2}}}{{\mathrm{p}}_{{\mathrm{CO}}_{2}}}=\frac{{(0.4)}^{2}}{0.4}=0.4\).

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