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The transition of electron that gives rise to the formation of the second spectral line of the Balmer series in the spec…

Q1

The transition of electron that gives rise to the formation of the second spectral line of the Balmer series in the spectrum of hydrogen atom corresponds to :

a

\({\mathrm{n}}_{\mathrm{f}}=2\) and \({\mathrm{n}}_{\mathrm{i}}=3\)

b

\({\mathrm{n}}_{\mathrm{f}}=3\) and \({\mathrm{n}}_{\mathrm{i}}=4\)

c

\({\mathrm{n}}_{\mathrm{f}}=2\) and \({\mathrm{n}}_{\mathrm{i}}=4\)

d

\({\mathrm{n}}_{\mathrm{f}}=2\)and \({\mathrm{n}}_{\mathrm{i}}=\infty\)

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