The energy of an electron in the ground state of hydrogen atom is -13.6 eV . The kinetic and potential energy of the ele…
The energy of an electron in the ground state of hydrogen atom is -13.6 eV . The kinetic and potential energy of the electron in the first excited state will be
\(3.4\mathrm{eV},-6.8\mathrm{eV}\)
For the first excited state of a hydrogen atom ( n=2), the kinetic energy is 3.4 eV and the potential energy is
\(-6.8\)eV. This is calculated using the formula for energy levels (\({E}_{n}=-13.6/{n}^{2}\)Sv6Kpe[] eV) and the relationship that potential energy (\(U\)Sv6Kpe[]) is equal to \(-2\)Sv6Kpe[] times the kinetic energy (\(K\)Sv6Kpe[]), with total energy (\(E\)Sv6Kpe[]) being the sum of both (\(E=K+U\)Sv6Kpe[]), and kinetic energy being the negative of the total energy (\(K=−E\))
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