An electron makes a transition from orbit n = 2 to orbit n = 1, in Bohr’s model of hydrogen atom. Consider change in magnitudes of its kinetic energy (K) and potential energy (U).

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Correct answer: a) K increases and U decreases. In Bohr's model of the hydrogen atom, the kinetic energy ($K$) and potential energy ($U$) of an electron in an orbit are related to its distance from the nucleus. When an electron transitions from a higher energy level ($n=2$) to a lower energy level ($n=1$), it loses energy. The kinetic energy of the electron is given by the formula $K = \frac{1}{2}mv^2$, and the potential energy is given by $U = -\frac{ke^2}{r}$, where $r$ is the radius of the orbit. As the electron moves to a lower orbit ($n=1$), the radius decreases, leading to an increase in kinetic energy (since the electron moves faster in lower orbits) and a decrease in potential energy (since it is closer to the nucleus). Therefore, $K$ increases and $U$ decreases. Identify the initial and final orbits: initial orbit $n=2$, final orbit $n=1$. Understand that as the electron moves to a lower orbit, it loses energy. Determine that kinetic energy increases because the electron moves faster in the lower orbit. Determine that potential energy decreases becaus

An electron makes a transition from orbit n = 2 to orbit n = 1, in Bohr’s model of hydrogen atom. Consider change in mag…

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