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If the wavelength of the first member of Lyman series of hydrogen is \( \lambda \). The wavelength of the second member …

Q1

If the wavelength of the first member of Lyman series of hydrogen is \( \lambda \). The wavelength of the second member will be;

a

\(\frac{32}{27} \lambda\)

b

\(\frac{27}{5} \lambda\)

c

\(\frac{27}{32} \lambda\)

d

\(\frac{5}{27} \lambda\)

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