Adiabatic constant of gas is 3/2. If volume of gas initially at ${0}^{\mathrm{o}}\mathrm{C}$ is reduced to one-fourth of the original volume then new temperature is (memory based jee mains shift-1 23/01/2025)

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Correct answer: d) $546\mathrm{K}$. In an adiabatic process, where no heat is exchanged, the relationship between temperature (T) and volume (V) for an ideal gas is given by: T V (γ - 1) = constant, Here, γ (gamma) Adiabatic constant of gas. T2 =546 K

Adiabatic constant of gas is 3/2. If volume of gas initially at \({0}^{\mathrm{o}}\mathrm{C}\) is reduced to one-fourth …

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