The total energy of an electron in the \( \mathrm{n}^{\text {th }} \) stationary orbit of the hydrogen atom can be obtai…

\( \mathrm{E}_{\mathrm{n}}=-\frac{13.6}{\mathrm{n}^{2}} \mathrm{eV} \)

\( \mathrm{E}_{\mathrm{n}}=-\frac{1.36}{\mathrm{n}^{2}} \mathrm{eV} \)

\( \mathrm{E}_{\mathrm{n}}=-13.6 \times \mathrm{n}^{2} \mathrm{eV} \)

\( \mathrm{E}_{\mathrm{n}}=\frac{13.6}{\mathrm{n}^{2}} \mathrm{eV} \)