In the first excited state of hydrogen atom, the energy of its electron is –3.4 eV. The radial distance of the electron from the hydrogen nucleus in this case is approximately :

(Take 1 eV = 1.6 × 10^–19 J, e = 1.6 × 10^–19 C and \(\frac{1}{4\pi {\epsilon }_{0}}\) = 9 × 10⁹ N m²/C²)

Question

In the first excited state of hydrogen atom, the energy of its electron is –3.4 eV. The radial distance of the electron from the hydrogen nucleus in this case is approximately :

(Take 1 eV = 1.6 × 10^–19 J, e = 1.6 × 10^–19 C and \(\frac{1}{4\pi {\epsilon }_{0}}\) = 9 × 10⁹ N m²/C²)

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In the first excited state of hydrogen atom, the energy of its electron is –3.4 eV. The radial distance of the electron …

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