\({}_{92}^{238}A\to {}_{90}^{234}B+{}_{2}^{4}D+Q\) In the given nuclear reaction, the approximate amount of energy relea…

\({}_{92}^{238}A\to {}_{90}^{234}B+{}_{2}^{4}D+Q\)

In the given nuclear reaction, the approximate amount of energy released will be:
[Given, mass of \({}_{92}^{238}A=238.05079\times 931.5\mathrm{MeV}/{\mathrm{c}}^{2}\), mass of \({}_{90}^{234}B=234.04363\times 931.5\mathrm{MeV}/{\mathrm{c}}^{2},\mathrm{m}\) as s of \({}_{2}^{4}D=4.00260\times 931.5\mathrm{MeV}/{\mathrm{c}}^{2}\) ]

[JEE Main 2023, 13 Apr (Shift 1)]