${}_{82}^{290}X\overset{\alpha }{\to }Y\overset{{\mathrm{e}}^{+}}{\to }Z\overset{{\beta }^{-}}{\to }P\overset{{\mathrm{e}}^{-}}{\to }Q$ In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are : [NEET 2024]

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YESPYQ · Accepted Answer

Correct answer: d) 286,81. $\begin{matrix}{}_{82}^{290}X\overset{\alpha }{\to }{\text{ }}_{80}^{286}Y\overset{{e}^{+}}{\to }{\text{ }}_{79}^{286}Z\overset{{\beta }^{−}}{\to }{\text{ }}_{80}^{286}P\overset{{e}^{−}}{\to }{\text{ }}_{81}^{286}Q \ A\to 286 \ Z=81\end{matrix}$

\({}_{82}^{290}X\overset{\alpha }{\to }Y\overset{{\mathrm{e}}^{+}}{\to }Z\overset{{\beta }^{-}}{\to }P\overset{{\mathrm{…

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