The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1.6 \(\over…

The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1.6 \(\overset{^\circ }{\mathrm{A}}\) apart is.\(\left(\mathrm{m}_{\mathrm{e}} \simeq 9 \times 10^{-31} \mathrm{~kg}, \quad \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}\right)\)\( \left(\right. \) Take \( \frac{1}{4 \pi \epsilon_{0}}=9 \times 10^{9} \mathrm{Nm}^{2} \mathrm{C}^{-2} \) )

[Re-NEET 2020]