The major product $C$ in the below mentioned reaction is : $C{H}_{3}C{H}_{2}C{H}_{2}Br\overset{Alc.KOH}{\underset{\Delta }{\to }}A\overset{HBr}{\to }B\overset{\text{Aq }KOH}{\underset{∆}{\to }}C$ [Re-NEET 2024]

Question

YESPYQ · Accepted Answer

Correct answer: b) Propan-2-ol. CH₃CH₂CH₂Br + alc. KOH (∆) → propene (elimination) propene + HBr → 2‐bromopropane (Markovnikov addition) 2‐bromopropane + aq. KOH → 2‐propanol (nucleophilic substitution).

The major product \(C\) in the below mentioned reaction is : \(C{H}_{3}C{H}_{2}C{H}_{2}Br\overset{Alc.KOH}{\underset{\De…

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