NEETChemistry

Haloalkanes and Haloarenes

5 NEET Chemistry previous year questions on Haloalkanes and Haloarenes — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ

The major product \(C\) in the below mentioned reaction is :
\(C{H}_{3}C{H}_{2}C{H}_{2}Br\overset{Alc.KOH}{\underset{\Delta }{\to }}A\overset{HBr}{\to }B\overset{\text{Aq  }KOH}{\underset{∆}{\to }}C\)

[Re-NEET 2024]

a

Propan-1-ol

b

Propan-2-ol

c

Propane

d

Propyne

✓ Correct answer: b)

Propan-2-ol

Explanation
  1. CH₃CH₂CH₂Br + alc. KOH (∆) → propene (elimination)

  2. propene + HBr2‐bromopropane (Markovnikov addition)

  3. 2‐bromopropane + aq. KOH2‐propanol (nucleophilic substitution).

Q2
PYQ

The major product \(C\) in the below mentioned reaction is :
\(C{H}_{3}C{H}_{2}C{H}_{2}Br\overset{Alc.KOH}{\underset{\Delta }{\to }}A\overset{HBr}{\to }B\overset{\text{Aq  }KOH}{\underset{∆}{\to }}C\)

[Re-NEET 2024]

a

Propan-1-ol

b

Propan-2-ol

c

Propane

d

Propyne

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Q3
PYQ

Elimination reaction of \(2\)-Bromopentane to form pent-\(2\)-ene is

(1) \( \beta \)-Elimination reaction

(2) Follows Zaitsev rule

(3) Dehydrohalogenation reaction

(4) Dehydration reaction

The set of correct statements is

[NEET 2020]

a

\((1),(3),(4)\) only

b

\((2),(3),(4)\) only

c

\((1),(2),(4)\) only

d

\((1),(2),(3)\) only

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Q4
PYQ

Assertion (A): Hydrolysis of an alkyl chloride is a slow reaction but in the presence of \(NaI\), the rate of the hydrolysis increases.
Reason (R): \(I ^{-}\)is a good nucleophile as well as a good leaving group.
In the light of the above statements, choose the correct answer from the options given below.

[JEE Main 2023, 24 Jan (Shift 1)]

a

(A) is false but ( \(R )\) is true.

b

(A) is true but (R) is false.

c

Both (A) and (R) are true and (R) is the correct explanation of (A).

d

Both (A) and (R) are true but (R) is NOT the correct explanation of (A).

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Q5
PYQ

Which of the following has the shortest \(\mathrm{C}-\mathrm{Cl}\) bond ?

[JEE Main 2020, 9 Jan (Shift 2)]

a

\(\mathrm{Cl}-\mathrm{CH}=\mathrm{CH}-{\mathrm{NO}}_{2}\)

b

\(\mathrm{Cl}-\mathrm{CH}=\mathrm{CH}-{\mathrm{CH}}_{3}\)

c

\(\mathrm{Cl}-\mathrm{CH}={\mathrm{CH}}_{2}\)

d

\(\mathrm{Cl}-\mathrm{CH}=\mathrm{CH}-{\mathrm{OCH}}_{3}\)

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