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The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is \(2400\m…

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The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is \(2400\mathrm{g}{\mathrm{cm}}^{2}\). The length of the 400 g rod is nearly :

[NEET 2024]

a

8.5 cm

b

17.5 cm

c

20.7 cm

d

72.0 cm

✓ Correct answer: a)

8.5 cm

Explanation

I = 2400 g cm², M = 400 g.

2400 = (400) x L² / 12

L² = (2400 x 12) / 400 = 6 x 12 = 72 cm².

L = √(36 x 2) = 6√2 cm ≈ 6 x 1.414 ≈ 8.48 cm.

(NEW NCERT 11th Page No. 114)

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