NEETPhysics

Rotational Motion

12 NEET Physics previous year questions on Rotational Motion — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ

The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is \(2400\mathrm{g}{\mathrm{cm}}^{2}\). The length of the 400 g rod is nearly :

[NEET 2024]

a

8.5 cm

b

17.5 cm

c

20.7 cm

d

72.0 cm

✓ Correct answer: a)

8.5 cm

Explanation

I = 2400 g cm², M = 400 g.

2400 = (400) x L² / 12

L² = (2400 x 12) / 400 = 6 x 12 = 72 cm².

L = √(36 x 2) = 6√2 cm ≈ 6 x 1.414 ≈ 8.48 cm.

(NEW NCERT 11th Page No. 114)

Q2
PYQ

The angular speed of a flywheel is increased from 600 rpm to 1200 rpm in 10 s. The number of revolutions completed by the flywheel during this time is :

a

600

b

900

c

300

d

150

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Q3
PYQ

The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is \(2400\mathrm{g}{\mathrm{cm}}^{2}\). The length of the 400 g rod is nearly :

[NEET 2024]

a

8.5 cm

b

17.5 cm

c

20.7 cm

d

72.0 cm

🔒
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Q4
PYQ

The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is \(2400\mathrm{g}{\mathrm{cm}}^{2}\). The length of the 400 g rod is nearly :

[NEET 2024]

a

8.5 cm

b

17.5 cm

c

20.7 cm

d

72.0 cm

🔒
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Q5
PYQ

A body rolls down an inclined plane without slipping. The kinetic energy of rotation is 50 % of its translational kinetic energy. The body is:

[JEE Main 2021, 20 Jul (Shift 2)]

a

Solid sphere

b

Solid cylinder

c

Hollow cylinder

d

Ring

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Q6
PYQ

Find the torque about the origin when a force of \( 3 \hat{j} \mathrm{~N} \) acts on a particle whose position vector is \( 2 \hat{k} \mathrm{~m} \).

a

\( 6 \hat{i} \mathrm{~N} \mathrm{~m} \)

b

\( 6 \hat{j} \mathrm{Nm} \)

c

\( -6 \hat{i} \mathrm{~N} \mathrm{~m} \)

d

\( 6 \hat{k} \mathrm{~N} \mathrm{~m} \)

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Q7
PYQ

The maximum and minimum distances of a comet from the Sun are \(1.6 \times 10^{12} m\) and \(8.0 \times 10^{10} m\) respectively. If the speed of the comet at the nearest point is \(6 \times 10^4\) \(ms ^{-1}\), the speed at the farthest point is:

[JEE Main 2021, 16 Mar (Shift 1)]

a

\(3.0 \times 10^3 m / s\)

b

\(1.5 \times 10^3 m / s\)

c

\(4.5 \times 10^3 m / s\)

d

\(6.0 \times 10^3 m / s\)

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Q8
PYQ

From a circular ring of mass \( M \) and radius \( R \) an arc corresponding to a \( 90^{\circ} \) sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is \( K \) times \( \mathrm{MR}^{2} \) . Then the value of \( \mathrm{K} \) is :

[NEET 2021]

a

\( \frac{1}{4} \)

b

\( \frac{1}{8} \)

c

\( \frac{3}{4} \)

d

\( \frac{7}{8} \)

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Q9
PYQ

The angular speed of the wheel of a vehicle is increased from \( 360 \mathrm{rpm} \) to \( 1200 \mathrm{rpm} \) in 14 second. Its angular acceleration is

[Re-NEET 2020]

a

\( 28 \pi \mathrm{rad} / \mathrm{s}^{2} \)

b

\( 120 \pi \mathrm{rad} / \mathrm{s}^{2} \)

c

\( 1 \mathrm{rad} / \mathrm{s}^{2} \)

d

\( 2 \pi \mathrm{rad} / \mathrm{s}^{2} \)

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Q10
PYQ

Find the torque about the origin when a force of \( 3 \hat{j} \mathrm{~N} \) acts on a particle whose position vector is \( 2 \hat{k} \mathrm{~m} \).

[NEET 2020]

a

\( 6 \hat{i} \mathrm{~N} \mathrm{~m} \)

b

\( 6 \hat{j} \mathrm{Nm} \)

c

\( -6 \hat{i} \mathrm{~N} \mathrm{~m} \)

d

\( 6 \hat{k} \mathrm{~N} \mathrm{~m} \)

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Q11
PYQ

The angular acceleration of a body, moving along the circumference of a circle, is :

a

along the radius towards the centre

b

along the tangent to its position

c

along the axis of rotation

d

along the radius, away from centre

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Q12
PYQ

The ratio of radius of gyration of a solid sphere of mass M and radius R about its own axis to the radius of gyration of the thin hollow sphere of same mass and radius about its axis is :-

a

5 : 3

b

\(\sqrt{\frac{3}{5}}\)

c

5 : 2

d

3 : 5

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