A compound X contains \(32%\) of A , \(20%\) of B and remaining percentage of C. Then, the empirical formula of X is (Gi…
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A compound X contains \(32%\) of A , \(20%\) of B and remaining percentage of C. Then, the empirical formula of X is
(Given atomic masses of \(\mathrm{A}=64\mathrm{u};\mathrm{B}=40\mathrm{u};\mathrm{C}=32\mathrm{u}\))
[NEET 2024]
✓ Correct answer: c)
\(AB{C}_{3}\)
Explanation
Assume 100 g of the compound.
A = 32 g, Moles of A = 32 / 64 = 0.5
B = 20 g, Moles of B = 20 / 40 = 0.5
C = 48 g, Moles of C = 48 / 32 = 1.5
Ratio
0.5 : 0.5 : 1.5
On multiplying by 2
1 : 1 : 3
Empirical formula
ABC₃
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