NEETChemistry

Some Basic Concepts of Chemistry

16 NEET Chemistry previous year questions on Some Basic Concepts of Chemistry — options free on every question; 2 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ
A metal chloride contains 55.0% of chlorine by weight. 100 mL vapours of the metal chloride at STP weigh 0.57 g. The molecular formula of the metal chloride is (Given: Atomic mass of chlorine is 35.5 u)
aMCl2
bMCl4
cMCl3
dMCl
✓ Correct answer: a) MCl2
ExplanationGiven: Mass = 0.57 g, Volume = 100 mL = 0.1 L At STP, molar volume = 22.4 L Moles = 0.1 / 22.4 = 0.004464 mol Molar mass = 0.57 / 0.004464 ≈ 127.7 g/mol Let metal chloride be MClₓ %Cl = (35.5x / (M + 35.5x)) × 100 = 55 Putting M + 35.5x = 127.7, solve: 35.5x = 70.24 ⇒ x = 2 So formula = MCl₂ Answer: Option A
Q2 FREE PREVIEW
PYQ

A compound X contains \(32\%\) of A , \(20\%\) of B and remaining percentage of C. Then, the empirical formula of X is
(Given atomic masses of \(\mathrm{A}=64\mathrm{u};\mathrm{B}=40\mathrm{u};\mathrm{C}=32\mathrm{u}\))

[NEET 2024]

a

\(AB{C}_{4}\)

b

\({A}_{2}B{C}_{2}\)

c

\(AB{C}_{3}\)

d

\(A{B}_{2}{C}_{2}\)

✓ Correct answer: c)

\(AB{C}_{3}\)

Explanation

Assume 100 g of the compound.

A = 32 g, Moles of A = 32 / 64 = 0.5

B = 20 g, Moles of B = 20 / 40 = 0.5

C = 48 g, Moles of C = 48 / 32 = 1.5

Ratio

0.5 : 0.5 : 1.5

On multiplying by 2

1 : 1 : 3

Empirical formula

ABC₃

Q3
PYQ

The highest number of helium atoms is in

[NEET 2024]

a

\(2.271098\mathrm{L}\) of helium at STP

b

\(4\) mol of helium

c

\(4\mathrm{u}\) of helium

d

\(4\mathrm{g}\) of helium

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Q4
PYQ

If 200 ml of 0.1 M Na2SO4 is mixed with 200 ml of 0.2 M BaCl2 solution. Total number of moles of all type of ions in the final solution is

a

0.18

b

0.12

c

0.14

d

0.22

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Q5
PYQ

On complete combustion, \(0.3 g\) of an organic compound gave \(0.2 g\) of \(CO _2\) and \(0.1 g\) of \(H _2 O\). The percentage composition of carbon and hydrogen in the compound, respectively are:

[Re-NEET 2024]

a

\(4.07 \%\) and \(15.02 \%\)

b

\(18.18 \%\) and \(3.70 \%\)

c

\(15.02 \%\) and \(4.07 \%\)

d

\(3.70 \%\) and \(18.18 \%\)

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Q6
PYQ

1 gram of sodium hydroxide was treated with \(25\mathrm{mL}\) of \(0.75\mathrm{M}\mathrm{HCl}\) solution, the mass of sodium hydroxide left unreacted is equal to

[NEET 2024]

a

200 mg

b

750 mg

c

250 mg

d

0 mg

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Q7
PYQ

Dalton's Atomic theory could not explain which of the following?

[NEET 2025]

a

Law of multiple proportion

b

Law of gaseous volume

c

Law of conservation of mass

d

Law of constant proportion

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Q8
PYQ

1.0 g of \(H _2\) has same number of molecules as in

[Re-NEET 2024]

a

\(14 g\) of \(N _2\)

b

\(18 g\) of \(H _2 O\)

c

\(16 g\) of \(CO\)

d

\(28 g\) of \(N _2\)

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Q9
PYQ

If 0.2 gram of an organic compound containing carbon, hydrogen and oxygen, on combustion yielded 0.147 grams of carbon dioxide and 0.12 grams of water. What will be the content of oxygen in the substance?

a

73.29%

b

78.45%

c

83.23%

d

89.50%

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Q10
PYQ

An ideal gaseous mixture of ethane (\({\mathrm{C}}_{2}{\mathrm{H}}_{6}\)) and ethene (\({\mathrm{C}}_{2}{\mathrm{H}}_{4}\)) occupies 28 liter at 1 atm and 273 K. The mixture reacts completely with 128 g \({\mathrm{O}}_{2}\)to produce \({\mathrm{CO}}_{2}\) and \({\mathrm{H}}_{2}\mathrm{O}\). The mole fraction at \({\mathrm{C}}_{2}{\mathrm{H}}_{6}\) in the mixture is:

a

0.6

b

0.4

c

0.5

d

0.8

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Q11
PYQ

When a hydrocarbon \(\mathrm{A}\) undergoes combustion in the presence of air, it requires 9.5 equivalents of oxygen and produces 3 equivalents of water. What is the molecular formula of A?

[JEE Main 2023, 29 Jan (Shift 2)]

a

\(\mathrm{C}_{8} \mathrm{H}_{6}\)

b

\(\mathrm{C}_{9} \mathrm{H}_{9}\)

c

\(\mathrm{C}_{6} \mathrm{H}_{6}\)

d

\(\mathrm{C}_{9} \mathrm{H}_{6}\)

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Q12
PYQ

Which one of the followings has maximum number of atoms?

[NEET 2020]

a

\( 1 \mathrm{~g} \) of \( \mathrm{Ag}~{(s)} \) [Atomic mass of \( \mathrm{Ag}=108 \) ]

b

\( 1 \mathrm{~g} \) of \( \mathrm{Mg}~{(s)} \) [Atomic mass of \( \mathrm{Mg}=24 \) ]

c

\( 1 \mathrm{~g} \) of \( \mathrm{O}_{2}~{(g)} \) [Atomic mass of \( \mathrm{O}=16 \) ]

d

\( 1 \mathrm{~g} \) of \( \mathrm{Li}~{(s)} \) [Atomic mass of \( \left.\mathrm{Li}=7\right] \)

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Q13
PYQ

Match List-I with List-II.

List - I List - II
(A) \(16 \mathrm{~g}\) of \(\mathrm{CH}_{4}(\mathrm{~g})\) (I) Weighs \(28 \mathrm{~g}\)
(B) \(1 \mathrm{~g}\) of \(\mathrm{H}_{2}(\mathrm{~g})\) (II) \(60.2 \times 10^{23}\) electrons
(C) 1 mole of \(\mathrm{N}_{2}(\mathrm{~g})\) (III) Weighs \(32 \mathrm{~g}\)
(D) \(0.5 \mathrm{~mol}\) of \(\mathrm{SO}_{2}(\mathrm{~g})\) (IV) Occupies \(11.4 \mathrm{~L}\) volume at STP

Choose the correct answer from the options given below:

[JEE Main 2023, 10 Apr (Shift 2)]

a

(A)-(I), B-(III), C-(II), D-(IV)

b

(A)-(II), B-(III), C-(IV), D-(I)

c

(A)-(II), B-(IV), C-(III), D-(I)

d

(A)-(II), B-(IV), C-(I), D-(III)

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Q14
PYQ

One mole of carbon atom weighs \( 12 \mathrm{~g} \), the number of atoms in it is equal to (Mass of carbon- 12 is \( 1.9926 \times 10^{-23} \mathrm{~g} \) )

[Re-NEET 2020]

a

\( 6.022 \times 10^{22} \)

b

\( 12 \times 10^{22} \)

c

\( 6.022 \times 10^{23} \)

d

\( 12 \times 10^{23} \)

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Q15
PYQ

The correct option for the mass of \(\mathrm{CO}_2\) produced by heating \(20 \mathrm{~g}\) of \(20 \%\) pure limestone is
(Atomic mass of \(\mathrm{Ca}=40\)u)
\(\left[{\mathrm{CaCO}}_{3}\overset{1200\mathrm{K}}{\to }\mathrm{CaO}+{\mathrm{CO}}_{2}\right]\)

[NEET 2023]

a

1.76 g

b

2.64 g

c

1.32 g

d

1.12 g

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Q16
PYQ

An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of \( \mathrm{C} \) is \( 12, \mathrm{H} \) is 1\( ] \)

[NEET 2021]

a

\( \mathrm{CH}_{2} \)

b

\( \mathrm{CH}_{3} \)

c

\( \mathrm{CH}_{4} \)

d

\( \mathrm{CH} \)

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