An object falls from a height of 10 m above the ground. After striking the ground it loses 50% of its kinetic energy. Th…

K.E. just before striking the ground \(K_1=m g h_1=m g(10)\)
K.E. just after striking the ground \(=K_1-\frac{50}{100} K_1=\frac{50}{100} K_1=\frac{K_1}{2}=K_2\)

Now, \(K_2=m g h_2\)

\(\begin{matrix}\Rightarrow \frac{{K}_{1}}{2}=mg{h}_{2} \\ \Rightarrow \frac{mg(10)}{2}=mg{h}_{2}\Rightarrow {h}_{2}=5m\end{matrix}\)