Work, Energy and Power

An object falls from a height of 10 m above the ground. After striking the ground it loses 50% of its kinetic energy. The height upto which the object can rebounce from the ground is:

[Re-NEET 2024]

At any instant of time $t$, the displacement of any particle is given by $2t-1$ (SI unit) under the influence of force of $5 \mathrm{N}$. The value of instantaneous power is (in SI unit):

[NEET 2024]

A particle of mass M moves along a horizontal x-axis from x=0 to x=L. The coefficient of kinetic friction varies as a function of x as ${\mu }_k$(x) = μ₀ − αx, where μ₀, α are constants of appropriate dimensions, so that ${\mu }_k$(L)=0. The total work done by the frictional force during the motion is nμ₀MgL, where g is the acceleration due to gravity. The value of n is:

[Re-NEET 2026]

The power of a crane, which lifts a mass of 1000 kg to a height of 20 m in 10 s is : $\left(g=9.8m/s^2\right)$

The amount of work done to raise a mass ‘m’ from the surface of the Earth to a height equal to the radius of the Earth ‘R’, will be:

An object moving along horizontal x-direction with kinetic energy $10 \mathrm{J}$ is displaced through $x=\left(3\hat{i}\right) \mathrm{m}$ by the force $\overrightarrow{\mathrm{F}}=(-2\hat{i}+3\hat{j})\mathrm{N}$. The kinetic energy of the object at the end of the displacement x is :

An object moving along horizontal x-direction with kinetic energy $10 \mathrm{J}$ is displaced through $x=\left(3\hat{i}\right) \mathrm{m}$ by the force $\overrightarrow{\mathrm{F}}=(-2\hat{i}+3\hat{j})\mathrm{N}$. The kinetic energy of the object at the end of the displacement x is :

[Re-NEET 2024]

An object moving along horizontal x-direction with kinetic energy $10 \mathrm{J}$ is displaced through $x=\left(3\hat{i}\right) \mathrm{m}$ by the force $\overrightarrow{\mathrm{F}}=(-2\hat{i}+3\hat{j})\mathrm{N}$. The kinetic energy of the object at the end of the displacement x is :

[Re-NEET 2024]

An object moving along horizontal x-direction with kinetic energy $10 \mathrm{J}$ is displaced through $x=\left(3\hat{i}\right) \mathrm{m}$ by the force $\overrightarrow{\mathrm{F}}=(-2\hat{i}+3\hat{j})\mathrm{N}$. The kinetic energy of the object at the end of the displacement x is :

[Re-NEET 2024]