Let $z=x+iy$ be a non-zero complex number such that ${\mathrm{z}}^{2}=i|\mathrm{z}{|}^{2}$, where $i=\sqrt{-1}$, then $\mathrm{z}$ lies on the : [JEE Main 2020, 6 Sep (Shift 2)]

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Let \(z=x+iy\) be a non-zero complex number such that \({\mathrm{z}}^{2}=i|\mathrm{z}{|}^{2}\), where \(i=\sqrt{-1}\), t…

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