Let \({z}_{1}\) and \({z}_{2}\) be two complex numbers such that \({z}_{1}+{z}_{2}=5\) and \({z}_{1}^{3}+{z}_{2}^{3}=20+…
Let \({z}_{1}\) and \({z}_{2}\) be two complex numbers such that \({z}_{1}+{z}_{2}=5\) and \({z}_{1}^{3}+{z}_{2}^{3}=20+15i\). Then, \(\left|{z}_{1}^{4}+{z}_{2}^{4}\right|\) equals
[JEE Main 2024, 31 Jan (Shift 2)]
75
\(z_1+z_2=5\)
\(z_1^3+z_2^3=20+15i\)
\(\left|z_1^4+z_2^4\right|=?\)
\(z_1^3+z_2^3=(z_1+z_2)^3-3z_1z_2(z_1+z_2)\)
\(z_1^3+z_2^3=125-15z_1z_2\)
\(20+15i=125-15z_1z_2\)
\(\Rightarrow z_1z_2=7-i\)
Now,
\((z_1+z_2)^2=5^2\)
\(z_1^2+z_2^2+2z_1z_2=25\)
\(z_1^2+z_2^2=25-2(7-i)\)
\(=11+2i\)
\((z_1^2+z_2^2)^2=(11+2i)^2\)
\(z_1^4+z_2^4+2(7-i)^2=117+44i\)
\(z_1^4+z_2^4=21+72i\)
\(\left|z_1^4+z_2^4\right|=\sqrt{21^2+72^2}\)
\(=\sqrt{441+5184}\)
\(=\sqrt{5625}\)
\(=75\)
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