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If \({V}_{0}\) is the gravitational potential due to sphere of uniform density on it's surface, then it's value at \(r=\…

Q1

If \({V}_{0}\) is the gravitational potential due to sphere of uniform density on it's surface, then it's value at \(r=\frac{R}{2}\) of sphere will be: (Radius of sphere = R)[JEE Main 2023, 11 Apr (Shift 2)]

a

\(\frac{11{V}_{0}}{8}\)

b

\(\frac{11}{7}{V}_{0}\)

c

\(\frac{14{V}_{0}}{3}\)

d

\(\frac{13{V}_{0}}{2}\)

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