Let \(K\) be the sum of the coefficients of the odd powers of \(x\) in the expansion of \((1+x{)}^{99}\) . Let a be the …
Q1
Let \(K\) be the sum of the coefficients of the odd powers of \(x\) in the expansion of \((1+x{)}^{99}\) . Let a be the middle term in the expansion of\({\left(2+\frac{1}{\sqrt{2}}\right)}^{200}\). If \(\frac{{}^{200}C_{99}K}{a}=\frac{{2}^{l}m}{n}\), where m and n are odd numbers, then the ordered pair (l, n) is equal to:
[JEE Main 2023, 29 Jan (Shift 2)]
🔒
Answer & explanation — PYQ Pass
Unlock · ₹149
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Maths PYQs
See every question on Binomial Theorem, or browse the full JEE question bank.
See all questions on Binomial Theorem →