🛠️ JEE🧪 Chemistry

The rate of a reaction decreased by \( 3.555 \) times when the temperature was changed from \( 40^{\circ} \mathrm{C} \) …

Q1

The rate of a reaction decreased by \( 3.555 \) times when the temperature was changed from \( 40^{\circ} \mathrm{C} \) to \( 30^{\circ} \mathrm{C} \). The activation energy ( in \( \mathrm{kJ} \mathrm{mol}^{-1} \) ) of the reaction is [to the nearest integer| Take; \( \mathrm{R}-8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} \ln 3.555-1.268 \)

[JEE Main 2020, 6 Sep (Shift 2)]

a

\(100\mathrm{kJ}/mole\)

b

\(200\mathrm{kJ}/mole\)

c

\(300\mathrm{kJ}/mole\)

d

\(400\mathrm{kJ}/mole\)

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