🛠️ JEE🧪 Chemistry

For a reaction taking place in three steps at same temperature, overall rate constant \(\mathrm{K}=\frac{\mathrm{K}_{1} …

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For a reaction taking place in three steps at same temperature, overall rate constant \(\mathrm{K}=\frac{\mathrm{K}_{1} \mathrm{~K}_{2}}{\mathrm{~K}_{3}}\). If \(\mathrm{Ea}_{1}, \mathrm{Ea}_{2}\) and \(\mathrm{Ea}_{3}\) are \(40,50\) and \(60 \mathrm{~kJ} / \mathrm{mol}\) respectively, the overall \(\mathrm{Ea}\) is ........... \(\mathrm{kJ} / \mathrm{mol}\).

[JEE Main 2024, 29 Jan (Shift 1)]

a

30

b

40

c

50

d

60

✓ Correct answer: a)

30

Explanation

By applying Arrhenius equation
\(K = \frac{K_1 \cdot K_2}{K_3} = \frac{A_1 \cdot A_2}{A_3} \cdot e^{-\frac{(E_{a1} + E_{a2} - E_{a3})}{RT}}\)
\(A \cdot e^{-E_a/RT} = \frac{A_1 A_2}{A_3} \cdot e^{-\frac{(E_{a1} + E_{a2} - E_{a3})}{RT}}\)
\(E_a = E_{a1} + E_{a2} - E_{a3} = 40 + 50 - 60\)
\(= 30 \text{ kJ/mole}\)

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