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A particle executes S.H.M. of amplitude A along \(x\)-axis. At \(t=0\), the position of the particle is \(x=\frac{A}{2}\…

Q1

A particle executes S.H.M. of amplitude A along \(x\)-axis. At \(t=0\), the position of the particle is \(x=\frac{A}{2}\) and it moves along positive \(x\)-direction. If the displacement of particle is \(x=A \sin (\omega t+\delta)\), then the value of \(\delta\) will be :

[JEE Main 2023, 10 Apr (Shift 1)]

a

\(\frac{\pi}{6}\)

b

\(\frac{\pi}{3}\)

c

\(\frac{\pi}{4}\)

d

\(\frac{\pi}{2}\)

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