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The equation of motion of a particle is given by \(x=a\sin (50t+\pi /3)cm\). The particle will come to rest at time \({t…

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The equation of motion of a particle is given by \(x=a\sin (50t+\pi /3)cm\). The particle will come to rest at time \({t}_{1}\) and it will have zero acceleration at time \({t}_{2}\). The \({t}_{1}\) and \({t}_{2}\) respectively are __________.

[02 April, 2026 (Shift-II)]

a

\(\frac{\pi }{300}s,\frac{\pi }{75}s\)

b

\(\frac{\pi }{75}s,\frac{\pi }{300}s\)

c

\(\frac{\pi }{300}s,\frac{\pi }{25}s\)

d

\(\frac{\pi }{50}s,\frac{\pi }{100}s\)

✓ Correct answer: a)

\(\frac{\pi }{300}s,\frac{\pi }{75}s\)

Explanation

At rest (v = 0):

\(\cos (50t+\pi /3)=0\Rightarrow 50t+\pi /3=\frac{\pi }{2}\)\({t}_{1}=\frac{\pi /2-\pi /3}{50}=\frac{\pi }{300}\)

Acceleration \(\left(a=-{\omega }^{2}x\right)\) :

\(a=-2500a\sin (50t+\pi /3)\)

For zero acceleration:

\(\sin (50t+\pi /3)=0\Rightarrow 50t+\pi /3=\pi\)

\({t}_{2}=\frac{\pi -\pi /3}{50}=\frac{\pi }{75}\)

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