The equation of motion of a particle is given by \(x=a\sin (50t+\pi /3)cm\). The particle will come to rest at time \({t…
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The equation of motion of a particle is given by \(x=a\sin (50t+\pi /3)cm\). The particle will come to rest at time \({t}_{1}\) and it will have zero acceleration at time \({t}_{2}\). The \({t}_{1}\) and \({t}_{2}\) respectively are __________.
[02 April, 2026 (Shift-II)]
✓ Correct answer: a)
\(\frac{\pi }{300}s,\frac{\pi }{75}s\)
Explanation
At rest (v = 0):
\(\cos (50t+\pi /3)=0\Rightarrow 50t+\pi /3=\frac{\pi }{2}\)\({t}_{1}=\frac{\pi /2-\pi /3}{50}=\frac{\pi }{300}\)
Acceleration \(\left(a=-{\omega }^{2}x\right)\) :
\(a=-2500a\sin (50t+\pi /3)\)
For zero acceleration:
\(\sin (50t+\pi /3)=0\Rightarrow 50t+\pi /3=\pi\)
\({t}_{2}=\frac{\pi -\pi /3}{50}=\frac{\pi }{75}\)
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