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The de Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_1\). If the temperature of…

Q1

The de Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_1\). If the temperature of the gas is increased to \(600 K\), then the de Broglie wavelength of the same gas molecule becomes:

[JEE Main 2023, 10 Apr (Shift 1)]

a

\(\frac{1}{\sqrt{2}} \lambda_1\)

b

\(2 \lambda_1\)

c

\(\frac{1}{2} \lambda_1\)

d

\(\sqrt{2} \lambda_1\)

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