The de Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_1\). If the temperature of…
Q1
The de Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_1\). If the temperature of the gas is increased to \(600 K\), then the de Broglie wavelength of the same gas molecule becomes:
[JEE Main 2023, 10 Apr (Shift 1)]
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