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In an experiment with photoelectric effect, the stopping potential, [JEE Main 2025, 29 Jan (Shift 2)]

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In an experiment with photoelectric effect, the stopping potential,

[JEE Main 2025, 29 Jan (Shift 2)]

a

is \(\left(\frac{1}{e}\right)\) times the maximum kinetic energy of the emitted photoelectrons

b

decreases with increase in the intensity of the incident light

c

increases with increase in the wavelength of the incident light

d

increases with increase in the intensity of the incident light

✓ Correct answer: a)

is \(\left(\frac{1}{e}\right)\) times the maximum kinetic energy of the emitted photoelectrons

Explanation

Energy of incoming photon

\(=hv=W+{K}_{\max }\)

The stopping potential \({V}_{s}\) is related to the maximum kinetic energy by:

\(e{V}_{s}={K}_{\max }\)

Correct answer is (a).

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