If the \({1011}^{\text{th }}\) term from the end in the binomial expansion of \({\left(\frac{4x}{5}-\frac{5}{2x}\right)}…

If the \({1011}^{\text{th }}\) term from the end in the binomial expansion of \({\left(\frac{4x}{5}-\frac{5}{2x}\right)}^{2022}\)is \(1024\) times \({1011}^{\text{th }}\)term from the beginning, then \(|x|\) is equal to

[JEE Main 2023, 11 Apr (Shift 2)]