The sum of the solution of the equation \( \frac{\cos x}{1+\sin x}=|\tan 2 x|, x \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)-\left\{\frac{\pi}{4},-\frac{\pi}{4}\right\} \) is:

[JEE Main 2021, 26 Aug (Shift 1)]

Question

The sum of the solution of the equation \( \frac{\cos x}{1+\sin x}=|\tan 2 x|, x \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)-\left\{\frac{\pi}{4},-\frac{\pi}{4}\right\} \) is:

[JEE Main 2021, 26 Aug (Shift 1)]

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The sum of the solution of the equation \( \frac{\cos x}{1+\sin x}=|\tan 2 x|, x \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\…

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