If the maximum distance of normal to the ellipse \(\frac{{x}^{2}}{4}+\frac{{y}^{2}}{{b}^{2}}=1,b<2\), from the origin is 1 , then the eccentricity of the ellipse is:

[JEE Main 2023, 31 Jan (Shift 1)]

Question

If the maximum distance of normal to the ellipse \(\frac{{x}^{2}}{4}+\frac{{y}^{2}}{{b}^{2}}=1,b [JEE Main 2023, 31 Jan (Shift 1)]

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If the maximum distance of normal to the ellipse \(\frac{{x}^{2}}{4}+\frac{{y}^{2}}{{b}^{2}}=1,b [JEE Main 2023, 31 Jan …