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An electron accelerated through a potential difference \(V_1\) has a de-Broglie wavelength of \(\lambda\). When the pote…

Q1

An electron accelerated through a potential difference \(V_1\) has a de-Broglie wavelength of \(\lambda\). When the potential is changed to \(V_2\), its de-Broglie wavelength increases by \(50 \%\). The value of \(\left(\frac{V_1}{V_2}\right)\) is equal to:

[JEE Main 2021, 27 Jul (Shift 1)]

a

\(
3
\)

b

\(
\frac{9}{4}
\)

c

\(
\frac{3}{2}
\)

d

\(
4
\)

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