Let $\left(a+b x+c x^2\right)^{10}=\sum_{i=0}^{20} p_i x^i, a, b, c \in N$.If $p_1=20$ and $p_2=210$, then $2(a+b+c)$ is equal to [JEE Main 2023, 15 Apr (Shift 1)]

Question

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

Let \(\left(a+b x+c x^2\right)^{10}=\sum_{i=0}^{20} p_i x^i, a, b, c \in N\).If \(p_1=20\) and \(p_2=210\), then \(2(a+b…

Practice more JEE Maths PYQs