Let \(x=2\) be a root of the equation \({x}^{2}+px+q=0\) and \(f\left(x\right)=\left{\begin{matrix}\frac{1-\cos \left({x…
Q1
Let \(x=2\) be a root of the equation \({x}^{2}+px+q=0\) and
\(f\left(x\right)=\left{\begin{matrix}\frac{1-\cos \left({x}^{2}-4px+{q}^{2}+8q+16\right)}{(x-2p{)}^{4}}, & x\neq 2p \\ 0 & x=2p\end{matrix}\right.\)
Then \(\lim _{x \rightarrow 2 p^{+}}[f(x)]\) where [.] denotes greatest integer function, is
[JEE Main 2023, 29 Jan (Shift 1)]
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