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Let \(f(x)\) be a continuously differentiable function on the interval \((0,\infty )\) such that \(f(1)=2\) and \(\lim _…

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Let \(f(x)\) be a continuously differentiable function on the interval \((0,\infty )\) such that \(f(1)=2\) and \(\lim _{t\to x}\frac{{t}^{10}f(x)-{x}^{10}f(t)}{{t}^{9}-{x}^{9}}=1\) for each \(x>0.\) Then, for all \(x>0, f(x)\) is equal to

[JEE Advanced 2024]

a

\(\frac{31}{11x}-\frac{9}{11}{x}^{10}\)

b

\(\frac{9}{11x}+\frac{13}{11}{x}^{10}\)

c

\(\frac{-9}{11x}+\frac{31}{11}{x}^{10}\)

d

\(\frac{13}{11x}+\frac{9}{11}{x}^{10}\)

✓ Correct answer: b)

\(\frac{9}{11x}+\frac{13}{11}{x}^{10}\)

Explanation

\(\lim_{t\to x}\frac{10t^9f(x)-f'(t)x^{10}}{9t^8}=1\)

\(\Rightarrow 10x^9f(x)-f'(x)x^{10}=9x^8\)

\(\Rightarrow f'(x)-\frac{10}{x}f(x)=-\frac{9}{x^2}\)

Let \(y=f(x)\).

\(IF=e^{-\int \frac{10}{x}\,dx}\)

\(IF=\frac{1}{x^{10}}\)

\(\frac{y}{x^{10}}=\int -\frac{9}{x^2}\cdot \frac{1}{x^{10}}\,dx\)

\(\frac{y}{x^{10}}=-9\int x^{-12}\,dx\)

\(\frac{y}{x^{10}}=\frac{9}{11}x^{-11}+C\)

\(\because y(1)=2\Rightarrow C=\frac{13}{11}\)

\(\Rightarrow y=\frac{9}{11x}+\frac{13}{11}x^{10}\)

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