Let \(f(x)\) be a continuously differentiable function on the interval \((0,\infty )\) such that \(f(1)=2\) and \(\lim _…
Let \(f(x)\) be a continuously differentiable function on the interval \((0,\infty )\) such that \(f(1)=2\) and \(\lim _{t\to x}\frac{{t}^{10}f(x)-{x}^{10}f(t)}{{t}^{9}-{x}^{9}}=1\) for each \(x>0.\) Then, for all \(x>0, f(x)\) is equal to
[JEE Advanced 2024]
\(\frac{9}{11x}+\frac{13}{11}{x}^{10}\)
\(\lim_{t\to x}\frac{10t^9f(x)-f'(t)x^{10}}{9t^8}=1\)
\(\Rightarrow 10x^9f(x)-f'(x)x^{10}=9x^8\)
\(\Rightarrow f'(x)-\frac{10}{x}f(x)=-\frac{9}{x^2}\)
Let \(y=f(x)\).
\(IF=e^{-\int \frac{10}{x}\,dx}\)
\(IF=\frac{1}{x^{10}}\)
\(\frac{y}{x^{10}}=\int -\frac{9}{x^2}\cdot \frac{1}{x^{10}}\,dx\)
\(\frac{y}{x^{10}}=-9\int x^{-12}\,dx\)
\(\frac{y}{x^{10}}=\frac{9}{11}x^{-11}+C\)
\(\because y(1)=2\Rightarrow C=\frac{13}{11}\)
\(\Rightarrow y=\frac{9}{11x}+\frac{13}{11}x^{10}\)
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