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The de Broglie wavelength of an electron having kinetic energy \(E\) is \(\lambda\). If the kinetic energy of electron b…

Q1

The de Broglie wavelength of an electron having kinetic energy \(E\) is \(\lambda\). If the kinetic energy of electron becomes \(\frac{E}{4}\), then its de-Broglie wavelength will be:

[JEE Main 2024, 29 Jan (Shift 1)]

a

\(
\frac{\lambda}{\sqrt{2}}
\)

b

\(
\frac{\lambda}{2}
\)

c

\(
2 \lambda
\)

d

\(
\sqrt{2} \lambda
\)

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