If the \(1011^{\text {th }}\) term from the end in the binomial expansion of \(\left(\frac{4 x}{5}-\frac{5}{2 x}\right)^…

If the \(1011^{\text {th }}\) term from the end in the binomial expansion of \(\left(\frac{4 x}{5}-\frac{5}{2 x}\right)^{2022}\) is 1024 times \(1011^{\text {th }}\) term from the beginning, then \(|x|\) is equal to

[JEE Main 2023, 11 Apr (Shift 2)]