\(\text{ Let }f:\left(-\frac{\pi }{4},\frac{\pi }{4}\right)\to R\text{ be defined as }\\ f(x)=\left{\begin{matrix}(1+|\s…

\(\text{ Let }f:\left(-\frac{\pi }{4},\frac{\pi }{4}\right)\to R\text{ be defined as }\\ f(x)=\left{\begin{matrix}(1+|\sin x|{)}^{\frac{3a}{|\sin x|}} & , & -\frac{\pi }{4}

\(\text{ If }f\text{ is continuous at }x=0\text{, then the value of }6a+{b}^{2}\text{ is equal to: }\)

[JEE Main 2021, 27 Jul (Shift 1)]