A natural number has prime factorization given by \( n=2^{x} 3^{y} 5^{z} \), where \( y \) and \( z \) are such that \( y+z=5 \) and \( y^{-1}+z^{-1}=\frac{5}{6}, y>z \). Then the number of odd divisors of, including 1 , is:

[JEE Main 2021, 26 Feb (Shift 2)]

Question

A natural number has prime factorization given by \( n=2^{x} 3^{y} 5^{z} \), where \( y \) and \( z \) are such that \( y+z=5 \) and \( y^{-1}+z^{-1}=\frac{5}{6}, y>z \). Then the number of odd divisors of, including 1 , is:

[JEE Main 2021, 26 Feb (Shift 2)]

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

A natural number has prime factorization given by \( n=2^{x} 3^{y} 5^{z} \), where \( y \) and \( z \) are such that \( …

Practice more JEE Maths PYQs