🛠️ JEE➗ Maths

Let \(\alpha, \beta, \gamma\) be the three roots of the equation \(x^3+b x+c=0\). If \(\beta \gamma=1=-\alpha\), then \(…

Q1

Let \(\alpha, \beta, \gamma\) be the three roots of the equation \(x^3+b x+c=0\). If \(\beta \gamma=1=-\alpha\), then \(b^3+2 c^3-3 \alpha^3-6 \beta^3-8 \gamma^3\) is equal to

[JEE Main 2023, 8 Apr (Shift 1)]

a

\(\frac{155}{8}\)

b

21

c

\(\frac{169}{8}\)

d

19

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

Practice more JEE Maths PYQs

See every question on Quadratic Equations, or browse the full JEE question bank.

See all questions on Quadratic Equations →