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The sum of the infinite series \(\frac{2^2}{2!}+\frac{2^4}{4!}+\frac{2^6}{6!}+\ldots\) is equal to

Q1

The sum of the infinite series \(\frac{2^2}{2!}+\frac{2^4}{4!}+\frac{2^6}{6!}+\ldots\) is equal to

a

\(\frac{\mathrm{e}^2+1}{2 \mathrm{e}}\)

b

\(\frac{\mathrm{e}^4+1}{2 \mathrm{e}^2}\)

c

\(\frac{\left(\mathrm{e}^2-1\right)^2}{2 \mathrm{e}^2}\)

d

\(\frac{\left(\mathrm{e}^2+1\right)^2}{2 \mathrm{e}^2}\)

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