🛠️ JEE🧪 Chemistry

The first order rate constant for the decomposition of \({\mathrm{CaCO}}_{3}\) at 700 K is \(6.36\times {10}^{-3}{\mathr…

Q1

The first order rate constant for the decomposition of \({\mathrm{CaCO}}_{3}\) at 700 K is \(6.36\times {10}^{-3}{\mathrm{s}}^{-1}\)and activation energy is 209kJ/mol. Its rate constant (in s-1) at 600 K is \(x\times {10}^{-6}\\\). The value of x is ____. (Nearest integer)

[ Given R = 8.314 J/K/ mol ; log \(6.36\times {10}^{-3}{\mathrm{s}}^{-1}\) = -2.19, \({10}^{-4.79}=1.62\times {10}^{-5}\)]

[JEE Main 2021, 27 Aug (Shift 2)]

a

10

b

12

c

14

d

16

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