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A force \(\vec{F}=(40\overset{^}{i}+10\overset{^}{j})N\) acts on a body of mass \(5\mathrm{kg}\). If the body starts fro…

Q1

A force \(\vec{F}=(40\overset{^}{i}+10\overset{^}{j})N\) acts on a body of mass \(5\mathrm{kg}\). If the body starts from rest, its position vector \(\vec{r}\) at time \(t=10\mathrm{s}\), will be:

[JEE Main 2021, 25 Jul (Shift 2)]

a

\((100\overset{^}{i}+100\overset{^}{j})m\)

b

\((400\overset{^}{i}+100\overset{^}{j})m\)

c

\((400\overset{^}{i}+400\overset{^}{j})m\)

d

\((100\overset{^}{i}+400\overset{^}{j})m\)

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