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If \(f(x)=\left{\begin{matrix}{e}^{x}+ax, & x

Q1

If \(f(x)=\left{\begin{matrix}{e}^{x}+ax, & x<0 \\ b{(x−1)}^{2}, & x\geq 0\end{matrix}\right.\)is differentiable at \(x=0\), then \((a,b)\) is

a

\((-3,-1)\)

b

\((-3,1)\)

c

(3, 1)

d

\((3,-1)\)

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