For the natural numbers $m, n$, if $(1-y)^m(1+y)^n=1+a_1 y$ $+a_2 y^2+\ldots a_{m+n} y^{m+n}$ and $a_1=a_2=10$, then the value of $(m+n)$ is equal to: [JEE Main 2021, 20 Jul (Shift 2)]

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For the natural numbers \(m, n\), if \((1-y)^m(1+y)^n=1+a_1 y\) \(+a_2 y^2+\ldots a_{m+n} y^{m+n}\) and \(a_1=a_2=10\), …

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