The difference between bond orders of CO and \({\mathrm{NO}}^{⊕}\)is \(\frac{\mathrm{X}}{2},\) then what is X? (Round of…
Q1
The difference between bond orders of CO and \({\mathrm{NO}}^{⊕}\)is \(\frac{\mathrm{X}}{2},\) then what is X?
(Round off to the nearest integer)
🔒
Answer & explanation — PYQ Pass
Unlock · ₹149
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Chemistry PYQs
See every question on Chemical Bonding and Molecular Structure, or browse the full JEE question bank.
See all questions on Chemical Bonding and Molecular Structure →