If \(x=\frac{1−{t}^{2}}{1+{t}^{2}}\) and \(y=\frac{2t}{1+{t}^{2}},\) then \(\frac{dy}{dx}\) is equal to:
Q1
If \(x=\frac{1−{t}^{2}}{1+{t}^{2}}\) and \(y=\frac{2t}{1+{t}^{2}},\) then \(\frac{dy}{dx}\) is equal to:
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